Question No. 6 △ABC is isosceles in which AE ⊥ BC, AE = 6 cm , BC = 9 cm, the area of △ABC is

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AE (Height of △ABC ) = 6 cm BC (Base of △ABC ) = 9 cm Area of △ABC = 1/2 X Base X Height = 1/2 X 6 X 9 =27 sq. cm.

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## Answers

AE (Height of △ABC ) = 6 cm

BC (Base of △ABC ) = 9 cm

Area of △ABC = 1/2 X Base X Height = 1/2 X 6 X 9 =27 sq. cm.